0=576-16t^2

Solution for 0=576-16t^2 equation:

0=576-16t^2

We move all terms to the left:

0-(576-16t^2)=0

We add all the numbers together, and all the variables

-(576-16t^2)=0

We get rid of parentheses

16t^2-576=0

a = 16; b = 0; c = -576;
Δ = b2-4ac
Δ = 02-4·16·(-576)
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36864}=192$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-192}{2*16}=\frac{-192}{32}
=-6
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+192}{2*16}=\frac{192}{32}
=6
$